Question

Find the composition $f \circ g$ of the functions $f(x) = \frac{x+3}{x^2}$, $g(x) = 3x+1$. 1. $(f \circ g)(x) = \frac{3x^2 + 10x + 3}{x^2}$ 2. $(f \circ g)(x) = \frac{3x+4}{9x^2 + 6x + 1}$ 3. $(f \circ g)(x) = \frac{x^2 + 6x + 9}{x^2}$ 4. $(f \circ g)(x) = \frac{x+3}{9x^2 + 6x + 1}$ 5. $(f \circ g)(x) = \frac{3x+4}{x^2}$

          Find the composition $f \circ g$ of the functions
$f(x) = \frac{x+3}{x^2}$, $g(x) = 3x+1$.
1. $(f \circ g)(x) = \frac{3x^2 + 10x + 3}{x^2}$
2. $(f \circ g)(x) = \frac{3x+4}{9x^2 + 6x + 1}$
3. $(f \circ g)(x) = \frac{x^2 + 6x + 9}{x^2}$
4. $(f \circ g)(x) = \frac{x+3}{9x^2 + 6x + 1}$
5. $(f \circ g)(x) = \frac{3x+4}{x^2}$
        
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Find the composition f ∘ g of the functions
f(x) = (x+3)/(x^2), g(x) = 3x+1.
1. (f ∘ g)(x) = (3x^2 + 10x + 3)/(x^2)
2. (f ∘ g)(x) = (3x+4)/(9x^2 + 6x + 1)
3. (f ∘ g)(x) = (x^2 + 6x + 9)/(x^2)
4. (f ∘ g)(x) = (x+3)/(9x^2 + 6x + 1)
5. (f ∘ g)(x) = (3x+4)/(x^2)

Added by Nancy M.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Find the composition f@g of the functions f(x)=(x+3)/(x^(2)),g(x)=3x+1. (f@g)(x)=(3x^(2)+10x+3)/(x^(2)) (f@g)(x)=(3x+4)/(9x^(2)+6x+1) (f@g)(x)=(x^(2)+6x+9)/(x^(2)) (f@g)(x)=(x+3)/(9x^(2)+6x+1) (f@g)(x)=(3x+4)/(x^(2)) Find the composition f o g of the functions x+3 f(x) = x2 g(x) = 3x+1. 3x2 +10x +3 1.(fog)(x) = x2 3x +4 2.(f og)(x) = 9x2+6x+1 x2+6x+9 3.(fog)(x) = x2 x+3 4.(f og)(x) = 9x2+6x+1 3x + 4 5.(f o g)(x) = x2
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Transcript

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00:01 So here we are given the function that is gx which is equals to x raised to the power 2 plus 3.
00:05 So we have to find out the function f that produces the given composition that is fog is equals to f of g of x is equals to x raised to the power 4 plus 6 of x raised to the power 2 plus 15.
00:18 So we have to find out the value of f of x where we are having the value of g of x.
00:24 So from here this is the value of g of x this is the value of f of g of x.
00:28 So the value of f of g of x is equals to x raised to the power 4 plus 6 of x raised to the power 2 plus 6 of x raised to the power 2 plus 15.
00:41 So this is the value of f of g of x.
00:44 So from here we can say that that the value of f of g of x g of x is x raised to the power 2 plus 3 which means that the value of f of x plus 2 is equals to x raised to the power 4 plus 6 of x raised to the power 2 plus 15 which means that the value of f of x raised to the power 2 plus 3 is equals to x raised to the power 4 plus 6 of x raised to the power 2 plus 9 plus 6.
01:14 So the value of f of x raised to the power 2 plus 3 become to x raised to the power 2 plus 3 to its whole square plus 6.
01:23 So we can write it as this is equals to this...
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