00:01
So, according to the question, first of all we will write the given function.
00:04
So it is given that fx is equal to ln 2 minus ln x and we have to evaluate its critical points.
00:11
Okay.
00:12
So we know that for critical points, for critical points, we have to put the value f dash x is equal to zero.
00:23
Okay.
00:23
So we know the differentiation formula for ln x.
00:27
Differentiation of ln x with respect to x is 1 upon x.
00:31
Okay.
00:32
So, now what can we do here? the f dash x value will be 1 upon 2 minus ln x.
00:40
Now by chain rule, we will differentiate 2 minus ln x again.
00:44
So d upon dx of 2 minus ln x.
00:47
So 1 upon 2 minus ln x and differentiation of 2 will be zero because it is constant minus of ln x is 1 upon x.
00:57
So f dash x value is minus 1 by x multiplied by 2 minus ln x.
01:02
Okay...