00:01
Hi here for the given function.
00:02
We need to find the value of critical point.
00:05
Then we need to check whether it is a local minimum maxima or a saddle point.
00:09
We are given that function f of xy is equal to 5x square plus 2 xy plus 4x plus y square plus y plus 3.
00:19
So here now in order to find the critical point first, we will take the partial derivative.
00:24
So del f upon del x is equal to 10x plus 2 y plus 4 is equal to 0 similarly the value of del f upon del y is equal to 2x plus 2 y plus 1 is equal to 0.
00:36
Let this be equation 1 and 2.
00:38
Now here solving equation 1 and 2 here.
00:41
We can say that we have value of x is equal to minus 3 by 8 and the value of y is equal to minus 1 by 8.
00:53
So here we can say that we have our required critical point is equal to minus 3 by 8 comma minus 1 by 8.
01:03
So here in order to check whether it is a saddle point maxima or minima point, we will consider the double derivative.
01:09
So the value of del square f upon del x square is equal to 2 the value of del square f upon del y square is equal to here...