Find the curvature K of the curve at the point P. r(t) = 6ti + 2t^2j, P(-6, 2) K =
Added by Erin M.
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r(t) = 6ti + 2t^2j r'(t) = dr/dt = 6i + 4tj r''(t) = d^2r/dt^2 = 0i + 4j Now, we need to find the point t corresponding to the point P(-6, 2). Since r(t) = 6ti + 2t^2j, we have: -6 = 6t => t = -1 2 = 2t^2 => t = -1 So, the point P corresponds to t = Show more…
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