Question

Find the derivative for the following functions: To make grading easier, please enter the derivative for each individual term in its own box in the order it was given a) f(x) = -2log7x + 8x2 + ?x f'(x) = b) y=2-7ln x - \frac{2}{x8} \frac{dy}{dx} = c) g(x) = -2x-2.8 - 2 \cdot 6x + 3x-7 g'(x) = d) y = 8ex + ?x + \frac{2}{x} y=

          Find the derivative for the following functions:
To make grading easier, please enter the derivative for each individual term in its own box in the
order it was given
a) f(x) = -2log<sub>7</sub>x + 8x<sup>2</sup> + ?x
f'(x) =
b) y=2-7ln x - \frac{2}{x<sup>8</sup>}
\frac{dy}{dx} =
c) g(x) = -2x<sup>-2.8</sup> - 2 \cdot 6<sup>x</sup> + 3x<sup>-7</sup>
g'(x) =
d) y = 8e<sup>x</sup> + ?x + \frac{2}{x}
y=

Find the derivative for the following functions:
To make grading easier, please enter the derivative for each individual term in its own box in the
order it was given
a) f(x) = -2log<sub>7</sub>x + 8x<sup>2</sup> + ?x
f'(x) =
b) y=2-7ln x - (2)/(x<sup>8</sup>)
(dy)/(dx) =
c) g(x) = -2x<sup>-2.8</sup> - 2 ·6<sup>x</sup> + 3x<sup>-7</sup>
g'(x) =
d) y = 8e<sup>x</sup> + ?x + (2)/(x)
y=

Added by Rachel B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

11/01/2023

Step 1

Step 1: a) f(x) = -2log7x + 8x2 + √x f'(x) = -2/xln7 + 16x + 1/2√x b) y=2-7ln z 2 28 Show more…

Show all steps

Thanks for your feedback!

Find the derivative for the following functions: To make grading easier, please enter the derivative for each individual term in its own box in the order it was given a) f(x) = -2log7x + 8x2 + √x f'(x) = b) y=2-7ln z 2 28 dy dr c) g(x) = -2x-2.8-2.62+3x-7 g'(x) = d) y = 8e² + √x+2 y=