Find the derivative of $f(x) = \frac{\ln(3x^3 + 3x^2)}{x}$
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Rewrite f(x) = ln(3x^3 + 3x^2) / x = ln(3x^3 + 3x^2) * x^{-1}, so use the product rule with u(x) = ln(3x^3 + 3x^2) and v(x) = x^{-1}. Show more…
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