Find the derivative of the following function. $y = \frac{1}{6 + 5\sin x}$ $\frac{dy}{dx} = \square$
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We use the chain rule to find the derivative. The chain rule states that if $y = f(g(x))$, then $\frac{dy}{dx} = f'(g(x))g'(x)$. In this case, $f(u) = u^{-1}$ and $g(x) = 6 + 5\sin x$. Then $f'(u) = -u^{-2}$ and $g'(x) = 5\cos x$. Show more…
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