Question

6. Find the derivative of the function and simplify. Show work to get full credit. $h(x) = \log_2 \sqrt[3]{2x + 1}$ $f(x) = x \arccos(x - 1)$

          6. Find the derivative of the function and simplify. Show work to get full credit.
$h(x) = \log_2 \sqrt[3]{2x + 1}$
$f(x) = x \arccos(x - 1)$

6. Find the derivative of the function and simplify. Show work to get full credit.
h(x) = log2 √(2x + 1)
f(x) = x arccos(x - 1)

Added by Desiree R.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Bradley Duda

07/14/2023

Step 1

h(x) = log_2(root(3)(2x+1)) First, rewrite the function using properties of logarithms: h(x) = (1/3) * log_2(2x+1) Now, differentiate h(x) with respect to x: h'(x) = (1/3) * (1/(2x+1)) * (2) * (1/ln(2)) Simplify the expression: h'(x) = (2/3) * (1/(2x+1)) * Show more…

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Find the derivative of the function and simplify. Show work to get full credit. h(x)=log_(2) oot(3)(2x+1),f(x)=xarccos(x-1) 6. Find the derivative of the function and simplify. Show work to get full credit h() = log2 /2 + 1 f() = x arccos(x -1)