Question

Find the derivative of the function and then evaluate at the given point. y=3x^2-4x, (-1,7) f'(x)= f'(-1)= (Type an integer or a simplified fraction.)

          Find the derivative of the function and then evaluate at the given point.
y=3x^2-4x, (-1,7)
f'(x)=
f'(-1)= (Type an integer or a simplified fraction.)

$Find the derivative of the function and then evaluate at the given point. y=3x^2-4x, (-1,7) f'(x)= f'(-1)= (Type an integer or a simplified fraction.)$

Added by Rebecca G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Pravin N

03/21/2022

Step 1

The derivative of y with respect to x is simply 1 (dy/dx), and the derivative of -3x with respect to x is -3. So, the derivative of the function is: (dy/dx) = 1 - 3 Show more…

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Find the derivative of the function and then evaluate it at the given point; y = 3x² - 4x (-1,7). f'(x)= f'(-1)= (Type an integer or a simplified fraction.)