00:01
In this problem it is given that f of x, y, z is equal to minus 3 e to the power x cos of y, z and the point p0 is given whose coordinate is 0, 0, 0 that is it lies at the origin and the vector a is given where a is equal to 3 i cap plus 5 j cap plus k cap.
00:37
Therefore, we have to find the partial derivative of x, y and z of the function f x, y, z.
00:44
Therefore, f x equals to del del x of f which is equal to minus 3 e to the power x cos of y, z and f of y is equal to del del y of f which is equal to 3 e to the power x sin of y, z, y, z and in the same way we find f z is equal to del del z of f this is equal to 3 e to the power x and sin of y, z.
01:31
Therefore, grad of f is equal to f x i cap plus f y j cap plus f z k cap.
01:49
So, we just put the values and this is equal to minus 3 e to the power x cos of y, z i cap plus 3 e to the power x z sin of y, z j cap plus plus 3 e to the power x y sin y, z and k cap.
02:31
So, at the point p whose coordinate is 0, 0, 0 grad of f is equal to minus 3 i cap plus 0 plus 0.
02:48
So, we have just put the values of x, y, z equals to 0, 0, 0 at the points and we have got minus 3 i...