Find the derivative of the function given below. y = 2 ·2^t...

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Transcript

00:01 With this problem, we are given line x is equals to negative 30 plus 5t, y is equals to 22 negative 4t, z is equals to negative 21 plus 4t and we have line 2 which is x is equals to 20 minus 3t, y is equals to 24 minus 6t, z is equals to negative 33 plus 8t.

00:30 So, we have to find the theta that is the angle.

00:37 So, first let us equate l1 is equals to l2.

00:40 First for x, we have negative 30 plus 5t is equals to 20 negative 33t.

00:48 So, we have 8t is equals to 50.

00:53 So, t is equals to 50 over 8 which implies t is equals to 6 .25.

01:04 So, now substituting this t is equals to 6 .25 in x, we get x is equals to negative 30 plus 5 multiplied by 6 .25 which implies x is equals to 1 .25.

01:23 So, moving on this is for x.

01:29 Next we have for y, again we are equating it 22 negative 4t is equals to 24 negative 6t.

01:40 So, we have 2t is equals to 2, therefore t is equals to 1.

01:47 So, for y is equals to 22 negative 4t, we have y is equals to 22 subtracted by 4 which gives y as 18.

02:00 So, for z we have negative 21 plus 4t is equals to negative 33 plus 8t.

02:08 So, we have 4t which is equals to 12.

02:21 So, t is equals to 3.

02:23 So, for z is equals to negative 21 plus 4 multiplied by 3 is equals to negative 21 plus 12...

Question

Find the derivative of the function given below. y = 2 \cdot 2^t + 6 \cdot 6^t NOTE: Enclose arguments of functions in parentheses. For example, $\sin(2x)$. $\frac{dy}{dt} = $

Question

Find the derivative of the function given below. y = 2 \cdot 2^t + 6 \cdot 6^t NOTE: Enclose arguments of functions in parentheses. For example, $\sin(2x)$. $\frac{dy}{dt} = $

Please give Ace some feedback