Find the derivative of the function. Simplify your answer.\\ y = \frac{8x^3}{8x - 7}\\ a) y' = \\ b) Use the derivative from part (a) to find x-values where the function has horizontal tangents.\\x =
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The quotient rule states that if we have a function in the form f(x)/g(x), the derivative is (f'(x)g(x) - f(x)g'(x))/(g(x))^2. Show more…
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