Question

Find the derivative y'(x) implicitly. $e^{5y} - \ln(y^2 - 1) = 3x$ A. $y'(x) = \frac{3(y^2 - 1)}{5(y^2 - 1)e^{5y} - 2y}$ B. $y'(x) = \frac{3(y^2 - 1)}{5(y^2 - 1)e^{5y} - 1}$ C. $y'(x) = \frac{(3 - 5e^{5x})(y^2 - 1)}{2y}$ D. $y'(x) = \frac{3(y^2 - 1) + 2y}{5(y^2 - 1)e^{5y}}$

Name: find the derivative yx implicitly e5y lny2 1 3x a yx frac3y2 15y2 1e5y 2y b yx frac3y2 15y2 1e5y 1 c yx frac3 5e5xy2 12y d yx frac3y2 1 2y5y2 1e5y 50454
Uploaded: 2022-03-02T02:04:09-08:00
Duration: 2 min 30 s
Channel: Gregory Higby
Description: find the derivative yx implicitly e5y lny2 1 3x a yx frac3y2 15y2 1e5y 2y b yx frac3y2 15y2 1e5y 1 c yx frac3 5e5xy2 12y d yx frac3y2 1 2y5y2 1e5y 50454

          Find the derivative y'(x) implicitly.
$e^{5y} - \ln(y^2 - 1) = 3x$
A. $y'(x) = \frac{3(y^2 - 1)}{5(y^2 - 1)e^{5y} - 2y}$
B. $y'(x) = \frac{3(y^2 - 1)}{5(y^2 - 1)e^{5y} - 1}$
C. $y'(x) = \frac{(3 - 5e^{5x})(y^2 - 1)}{2y}$
D. $y'(x) = \frac{3(y^2 - 1) + 2y}{5(y^2 - 1)e^{5y}}$

$find the derivative yx implicitly e5y lny2 1 3x a yx frac3y2 15y2 1e5y 2y b yx frac3y2 15y2 1e5y 1 c yx frac3 5e5xy2 12y d yx frac3y2 1 2y5y2 1e5y 50454$

Added by Lisa C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Gregory Higby

03/02/2022

Step 1

$\frac{d}{dx}(e^{5y} - \ln(y^2 - 1)) = \frac{d}{dx}(3x)$ $\frac{d}{dx}(e^{5y}) - \frac{d}{dx}(\ln(y^2 - 1)) = 3$ Show more…

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Find the derivative y'(x) implicitly. $e^{5y} - \ln(y^2 - 1) = 3x$ A. $y'(x) = \frac{3(y^2 - 1)}{5(y^2 - 1)e^{5y} - 2y}$ B. $y'(x) = \frac{3(y^2 - 1)}{5(y^2 - 1)e^{5y} - 1}$ C. $y'(x) = \frac{(3 - 5e^{5x})(y^2 - 1)}{2y}$ D. $y'(x) = \frac{3(y^2 - 1) + 2y}{5(y^2 - 1)e^{5y}}$