Find the equation of the plane through the point P = (4, 4, 2) and parallel to the plane -(2x + 2y + 5z) = 6. z =
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This means that they have the same normal vector. The normal vector of the given plane is (-2, -2, -5). Second, we know that the plane we are looking for passes through the point P=(4,4,2). This means that when we substitute these coordinates into the equation of Show more…
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