Find the equation for the line tangent to the curve at the point defined by the given value of t. Also, find dĀ²y/dxĀ² at this point. x = 2tĀ² + 5, y = tā“, t = -1
Added by Tara M.
Step 1
Given x = 2t^2 + 5 and y = t^4, plug in t = -1: x = 2(-1)^2 + 5 = 2 + 5 = 7 y = (-1)^4 = 1 So the point on the curve is (7, 1). Show moreā¦
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