Question

1. Find the equation of a line passing through the point (3, 4), and the center of the circle whose equation is $x^2 - 4x + y^2 - 2y - 1 = 0$.

Name: 1. Find the equation of a line passing through the point (3, 4), and the center of the circle whose equation is x^2 - 4x + y^2 - 2y - 1 = 0.
Uploaded: 2023-08-24T11:00:50-08:00
Duration: 1 min 4 s
Channel: Sri K
Description: 1. Find the equation of a line passing through the point (3, 4), and the center of the circle whose equation is x^2 - 4x + y^2 - 2y - 1 = 0.

          1. Find the equation of a line passing through the point (3, 4), and the center of the circle whose equation is $x^2 - 4x + y^2 - 2y - 1 = 0$.

Added by Willie H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sri K

08/24/2023

Step 1

Given equation of the circle: x^2 - 4x + y^2 - 2y - 1 = 0 Rearranging terms: (x^2 - 4x) + (y^2 - 2y) = 1 Completing the square for x terms: (x^2 - 4x + 4) + (y^2 - 2y) = 1 + 4 (x - 2)^2 + (y^2 - 2y) = 5 Completing the square for y terms: (x - 2)^2 + (y^2 - 2y Show more…

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Find the equation of a line passing through the point (3,4), and the center of the circle whose equation is x^(2)-4x+y^(2)-2y-1=0. 1.Find the equation of a line passing through the point(3,4),and the center of the circle whose equation isx-4x+y2-2y-1=0