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Hello students, in the question we are asked to find the equation of family of curve whose slopes are.
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So we have four parts.
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In part a, a slope is 3x square plus 4.
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So we know that d divided by dx is equals to 3x square plus 4.
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So now separating this, we get dy is equal to 3x square plus 4 multiplied by dx.
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Now integrating both sides, integrating both sides, we get integration d ,y is equal to integration 3x square plus 4 multiplied by dx.
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So solving this, we get y is equal to 3x cubed divided by 3 plus 4x plus c.
00:53
So from here we get y is equal to x q plus 4x plus c.
00:59
So this is our equation of family of curve.
01:03
Now in part b, in part b we are given x divided by y.
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So our equation will be dyy d x is equals to x divided by y.
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Separating terms we get y -d -y is equal to x -tx.
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Now integrating both sides, integrating, integrating, integrating both sides, both sides, we get integration y, d ,y is equals to integration x, dx.
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So, solving this, we get, solving this, we get y squared divided by 2 is equals to x square divided by 2 plus c.
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So from here, we get the equation y square is equal to x square plus 2c.
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So this is our equation...