Find the equation of the line tangent to the curve defined by x^5+2xy+y^3=48 at the point (2,2). y=
Added by Michael C.
Step 1
Using implicit differentiation, we get: \[ \frac{d}{dx}(x^5) + \frac{d}{dx}(2xy) + \frac{d}{dx}(y^3) = \frac{d}{dx}(48) \] Show more…
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