Find the equation of the line tangent to the graph of f at the indicated value of x. f(x) = 1 - 5 ln x; x = 1 y =
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Given that \( f(x) = 1 - 5\ln(x) \) and \( x = 1 \), we can find the point of tangency by evaluating \( f(1) \). \[ f(1) = 1 - 5\ln(1) = 1 - 5(0) = 1 \] So, the point of tangency is \( (1, 1) \). Show more…
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