Find the equation of the normal line to the tangent line y=5/4x-3 at the point (4, 2).
Added by James T.
Step 1
The given equation of the tangent line is \( y = \frac{5}{4}x - 3 \). The slope of this line is the coefficient of \( x \), which is \( \frac{5}{4} \). Show more…
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