Question

Find the equation of the tangent line at the point $(-1, 1)$ to the curve defined implicitly below. $x^6 + y^3 = 2$

          Find the equation of the tangent line at the point $(-1, 1)$ to the curve defined implicitly below.
$x^6 + y^3 = 2$

Added by Celia M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Heather Eichman

03/10/2021

Step 1

For the curve x^6 + y^3 = 2, we differentiate both sides with respect to x using implicit differentiation: 6x^5 + 3y^2(dy/dx) = 0 Solving for dy/dx, we get: dy/dx = -2x^5 / y^2 Show more…

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Find the equation of the tangent line at the point (-1,1) to the curve defined implicitly below. x^(6)+y^(3)=2 Find the equation of the tangent line at the point (1,1) to the curve defined implicitly below. 6+y3=2