Find the equation of the tangent line to the graph of $x^2y - xy^5 = -2032$ at $(2, 4)$. (Remember to include \"y=\" in your answer
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The given equation is x^2*y - x*y^5 = -2032. Taking the derivative of both sides with respect to x: d/dx (x^2*y) - d/dx (x*y^5) = d/dx (-2032) 2xy + x^2(dy/dx) - y^5 - 5xy^4(dy/dx) = 0 Simplify the equation: dy/dx = (y^5 - 2xy) / (x^2 - 5xy^4) Show more…
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