Question

(a) Find the equation of the tangent line to the parametric curve x = 1 + 3t and y = 2 - t^2 at the point (10, -7).

Name: (a) Find the equation of the tangent line to the parametric curve x = 1 + 3t and y = 2 - t^2 at the point (10, -7).
Uploaded: 2023-05-16T11:57:29-08:00
Duration: 2 min 56 s
Channel: Sanchit Jain
Description: (a) Find the equation of the tangent line to the parametric curve x = 1 + 3t and y = 2 - t^2 at the point (10, -7).

          (a) Find the equation of the tangent line to the parametric curve x = 1 + 3t and y = 2 - t^2 at the point (10, -7).

Added by Angelica T.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Sanchit Jain

05/16/2023

Step 1

Given: x = 1 + 3t y = 2 - t^2 dy/dx = dy/dt / dx/dt dy/dt = -2t dx/dt = 3 dy/dx = (-2t) / 3 dy/dx = -2/3 Show more…

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(a) Find the equation of the tangent line to the parametric curve x = 1 + 3t and y = 2 - t^2 at the point (10, -7).

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