Find the E($X^2 - 2x$) + E(5) and V(5X + 6) of the following probability distribution: X: 1, 2, 3, 4, 5 P(X): 1/6, 1/6, 1/6, 1/6, 1/6
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$E(X) = \sum_{i=1}^{5} x_i P(x_i) = 1(\frac{1}{6}) + 2(\frac{1}{6}) + 3(\frac{1}{6}) + 4(\frac{1}{6}) + 5(\frac{1}{6}) = \frac{15}{6} = \frac{5}{2} = 2.5$ Show more…
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