Find the exact area under the curve between the indicated values of x. 2) y = 2x - x²; between x = 0 and x = 2
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∫(2x - x^2) dx = ∫(2x) dx - ∫(x^2) dx Now, we find the antiderivative of each term: ∫(2x) dx = x^2 + C_1 ∫(x^2) dx = (1/3)x^3 + C_2 Now, we combine the antiderivatives: ∫(2x - x^2) dx = x^2 - (1/3)x^3 + C Show more…
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