Find the exact value without a calculator. \[ \cos 15^{\circ}=\frac{\sqrt{[?]+\sqrt{\square}}}{\square} \] Double-Angle Formulas: \( \sin (2 \theta)=2 \sin \theta \cos \theta \) \( \cos (2 \theta)=\cos ^{2} \theta-\sin ^{2} \theta \) \( \tan (2 \theta)=\frac{2 \tan \theta}{1-\tan ^{2} \theta} \) Half-Angle Formulas: \( \sin \left(\frac{\theta}{2}\right)= \pm \sqrt{\frac{1-\cos \theta}{2}} \) \( \cos \left(\frac{\theta}{2}\right)= \pm \sqrt{\frac{1+\cos \theta}{2}} \) \( \tan \left(\frac{\theta}{2}\right)= \pm \sqrt{\frac{1-\cos \theta}{1+\cos \theta}} \)
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Therefore, we can use the half-angle formula for cosine: \[ \cos \left(\frac{\theta}{2}\right) = \pm \sqrt{\frac{1 + \cos \theta}{2}} \] Show more…
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