The illuminance of a point on a surface by a source of light: $E=\frac{I \cos \theta}{r^{2}}$.
The illuminance $E$ (in lumens/m $^{2}$ ) of a point on a horizontal surface is given by the formula shown, where $I$ is the intensity of the light source in lumens, $r$ is the distance in meters from the light source to the point, and $\theta$ is the complement of the angle $\alpha$ (in degrees) made by the light source and the horizontal surface. Calculate the illuminance if $I=800$ lumens, and the flashlight is held so that the distance $r$ is $2 \mathrm{m}$ while the angle $\alpha$ is $40^{\circ}$.
CAN'T COPY THE FIGURE