Find the following integrals " (−3x + 4)e−3x2+8xdx
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Step 1
Let u = -3x^2 + 8x. Then, the derivative of u with respect to x is du/dx = -6x + 8. Now, we can rewrite the integral in terms of u: ∫(−3x + 4)e^(-3x^2+8x)dx = ∫(1/2)(-6x + 8)e^u du/dx dx Now, we can see that the (-6x + 8) term is the derivative of u, so we can Show more…
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