Find the following limit or state that it does not exist. $$lim_{x \to -5} \frac{2(2x+3)^2-98}{x+5}$$ Simplify the given limit. $$lim_{x \to -5} \frac{2(2x+3)^2-98}{x+5} = lim_{x \to -5} \boxed{}$$ (Simplify your answer.)
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$$lim_{x \to -5} \frac{2(2x+3)^2-98}{x+5} = lim_{x \to -5} \frac{2[(2x+3)^2-49]}{x+5}$$ Show more…
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