Find the following z values for the standard normal variable Z. Note: You may find it useful to reference the z table. Negative values should b 2 decimal places. a. P(Z? z) = 0.8485 b. P(Z> z) = 0.7329 c. P(-z? Z?z) = 0.96 d. P(0 ? Z?z) = 0.2517
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8485. Looking at the z-table, we find that the z-score corresponding to an area of 0.8485 is approximately 1.03. Show more…
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