00:01
So the interval first we need to write here that is minus 1 comma 1 and it includes the ability to divide the function into two series.
00:11
So that is f1 x is equal to 0 for x is less than 2 minus 1 and greater than 2 minus of 2.
00:22
So from here f2 x is equal to we have to write here minus of 8 for x is less than 2 0 and greater than equal to 2 minus of 1.
00:38
F3 x is equal to 1 at 1 when x is less than 2 1 and greater than 2 0 and f4 x is equal to 0 when x is less than 2 2 and greater than 2 1.
00:58
So this is we have given here.
01:00
So from here according to fourier series first we need to find here a0.
01:05
So that is 1 by 2 integration minus 1 to 0 and that is minus 1 dx and plus integration 0 to 1 1 dx.
01:23
So after integrating this function we will get we need to write here minus of 8.
01:29
So after integrating we will get from here that is 2 and it become from there that is minus 8 plus 1 and which is equal to we have here minus 7 by 2.
01:49
This is our first answer.
01:52
Now we need to find our an value.
01:55
So an value is equal to we have here that is equal to 1 by 2 integration minus 1 to 0 and that is minus 8 cos n pi x by 2 plus integration 0 to 1 it is cos n pi x by with respect to dx...