Question

P 6.19 The input to the filter is $v_{in}(t) = 3 + 4cos(1000\pi t) + sin(2000\pi t) + 4cos(3000\pi t)$ V and the output is $v_{out}(t) = 3 + 2cos(1000\pi t + 50^\circ) + 3sin(3000\pi t)$ V.

          P 6.19
The input to the filter is
$v_{in}(t) = 3 + 4cos(1000\pi t) + sin(2000\pi t) + 4cos(3000\pi t)$
V and the output is
$v_{out}(t) = 3 + 2cos(1000\pi t + 50^\circ) + 3sin(3000\pi t)$ V.

P 6.19
The input to the filter is
vin(t) = 3 + 4cos(1000π t) + sin(2000π t) + 4cos(3000π t)
V and the output is
vout(t) = 3 + 2cos(1000π t + 50^∘) + 3sin(3000π t) V.

Added by Robert W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Krishna J

Step 1

From the given input and output signals, we can see that the input signal contains four frequency components: 100ω, 200ω, 3000ω, and the DC component (0 Hz). The output signal contains three frequency components: 100ω, 300ω, and the DC component (0 Hz). To find Show more…

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Find the frequencies for f1, f2, f3, f4 in Hz. Determine the transfer function for 0 Hz. Determine the transfer function for 500 Hz. Determine the transfer function for 1500 Hz. Please and thanks!! P 6.19 The input to the filter is vin(t) = 3 + 4cos(100Ï‰t) + sin(200Ï‰t) + 4cos(3000Ï‰t) V and the output is vout(t) = 3 + 2cos(100Ï‰t + 50) + 3sin(300Ï‰t) V.