Question

Find the function \( y=y(x) \) (for \( x>0 \) ) which satisfies the separable differential equation \[ \frac{d y}{d x}=\frac{2+19 x}{x y^{2}} \quad x>0 \] with the initial condition \( y(1)=6 \). \[ y= \] \( \square \) Question Help: Video Written Example

          Find the function \( y=y(x) \) (for \( x>0 \) ) which satisfies the separable differential equation
\[
\frac{d y}{d x}=\frac{2+19 x}{x y^{2}} \quad x>0
\]
with the initial condition \( y(1)=6 \).
\[
y=
\]
\( \square \)
Question Help:
Video
Written Example

Find the function y=y(x) (for x>0 ) which satisfies the separable differential equation

(d y)/(d x)=(2+19 x)/(x y^2) x>0

with the initial condition y(1)=6.

y=

□
Question Help:
Video
Written Example

Added by Stephen C.

Calculus and Its Applications

Larry J. Goldstein, David C. Lay, David… 14th Edition

Chapter 5

Instant Answer

Solved by Expert Darryl Burns

Step 1

Step 1: Start with the given differential equation \[ \frac{d y}{d x} = \frac{2 + 19x}{x y^2} \] Show more…

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Find the function \( y=y(x) \) (for \( x>0 \) ) which satisfies the separable differential equation \[ \frac{d y}{d x}=\frac{2+19 x}{x y^{2}} \quad x>0 \] with the initial condition \( y(1)=6 \). \[ y= \] \( \square \) Question Help: Video Written Example