Question

Find the general antiderivative of $\int(\frac{4}{x} + \frac{4}{x^2} + \sin(4x))dx$. $\circ \frac{2}{x^2} - \frac{12}{x^3} - \cos(4x) + C$ $\circ 4\ln|x| - \frac{4}{x} - 4\cos(4x) + C$ $\circ 4\ln|x| - \frac{4}{x} - \frac{1}{4}\cos(4x) + C$ $\circ 4\ln|x| + \frac{4}{x} + \frac{1}{4}\cos(4x) + C$

          Find the general antiderivative of $\int(\frac{4}{x} + \frac{4}{x^2} + \sin(4x))dx$.
$\circ \frac{2}{x^2} - \frac{12}{x^3} - \cos(4x) + C$
$\circ 4\ln|x| - \frac{4}{x} - 4\cos(4x) + C$
$\circ 4\ln|x| - \frac{4}{x} - \frac{1}{4}\cos(4x) + C$
$\circ 4\ln|x| + \frac{4}{x} + \frac{1}{4}\cos(4x) + C$

Find the general antiderivative of ∫((4)/(x) + (4)/(x^2) + sin(4x))dx.
∘(2)/(x^2) - (12)/(x^3) - cos(4x) + C
∘ 4ln|x| - (4)/(x) - 4cos(4x) + C
∘ 4ln|x| - (4)/(x) - (1)/(4)cos(4x) + C
∘ 4ln|x| + (4)/(x) + (1)/(4)cos(4x) + C

Added by Philip S.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ernest Castorena

06/01/2020

Step 1

Step 1: Split the integral: ∫(4/x + 4/x^2 + sin(4x)) dx = ∫4/x dx + ∫4/x^2 dx + ∫sin(4x) dx. Show more…

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