00:01
Hi, from the question given that here in part a we need to find the general solution of the given differential equation.
00:08
So, first d squared y by dx squared minus 9y is equal to 0 so that the auxiliary equation will be m squared minus 9 is equal to 0.
00:21
So, m squared is equal to 9.
00:23
So, m is equal to plus or minus 3.
00:26
So, that the general solution y of x is equal to c1 e to the power of 3x plus c2 e to the power of minus 3x.
00:35
Now, let us move on to the second one.
00:39
So, in the second one, this is first one, 2 times of d squared y by dx squared plus 16 dy by dx plus 32 y is equal to 0.
00:52
So, here is also first we need to find the auxiliary equation.
00:55
So, auxiliary equation can be written as 2m squared plus 16m plus 32 is equal to 0.
01:03
So, we need to factorize 64 as 8 8 z.
01:08
So, we have 2m squared plus 8m plus 8m plus 32 is equal to 0.
01:15
So, here we need to take 2m as a common.
01:18
So, m plus 4m not m.
01:23
So, we have already taken m here.
01:25
So, m plus 4 plus taken 8.
01:28
So, we have m plus 4.
01:30
So, that is equal to 0.
01:32
So, that the factors are 2m plus 8 times of m plus 4 which is equal to 0.
01:40
So, here the value of m is equal to minus 8 by 2 is minus 4 and m is equal to minus 4.
01:47
So, this is the factors.
01:48
Therefore, the general solution will be y of x is equal to ax plus b times e to the power of minus 4x.
02:00
And in the third part it is given that b squared y by dx squared plus 4 dy by dx plus 5y is equal to 0.
02:14
So, that the auxiliary equation is m squared plus 4m plus 5 is equal to 0.
02:21
So, when we factorize this m is equal to minus 4 plus or minus square root of b squared is 16 minus 4 times of a is 1 c is 5 divided by 2.
02:36
So, that is equal to minus 4 plus or minus square root of 16 minus 20 became minus 4 divided by 2.
02:43
So, that is equal to minus 4 plus or minus 2i divided by 2.
02:49
So, which is equal to minus 2 plus or minus i.
02:55
Therefore, the general solution will be y of x is equal to e power minus 2x times c1 cos x plus c2 sin x.
03:08
Now, let us move on to the second part...