Find the general solution of the differential equation: $4xy' - 2y = -\frac{x^2}{y^3}$. Use lower case $c$ for the constant in answer. y =
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Step 1: Rewrite the given differential equation in standard form by dividing by 4x: y' - (1/2)(y/x) = -(1/4)(x^2)/(y^3) Show more…
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