00:01
So, as per question let us consider a is the matrix which is in first row we have 1, 3, 4, in second row we have 3, 9, 7 and this whole is divided by 7 and 6.
00:18
So, the main objective is to find the general solution of the system.
00:22
So, now we will transform this matrix into v changes r2 into r2 minus 3r1.
00:30
So, by doing this we get in the first row we have 1, 3, 4 and here we have 7 and in second row we have 0, 0, minus 5 and here we have minus 15.
00:47
So, now we will write the system of equation using the above matrix as follows.
00:52
We have now x1 plus 3x2 plus 4x3 it is equal to the 7 and this is our first equation and we have minus 5x3 is equal to the minus 15 and suppose this is our second equation...