Find the general solution to the linear first-order differential equation: $\frac{dy}{dx} + \frac{3x}{x^2+1}y = \frac{6x}{x^2+1}$ Show all steps
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The given differential equation is: 6x To write it in the standard form, we need to express it as: dy/dx = f(x) In this case, f(x) = 6x. So, the standard form of the differential equation is: dy/dx = 6x Show more…
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