Question

Find the intersection point(s) of the graphs of \( y=\frac{1}{2}(x-2)^{2}+\frac{3}{2} \) and \( y=2(x-2)(x+1) \). 1) \( (2 \pm \sqrt{2}, 1 \pm 6 \sqrt{2}) \) (2) \( \left(\frac{1}{15}, \frac{4}{9}\right) \) 3 There are no intersection points. \( 4(\sqrt{5}, 6-2 \sqrt{5}) \) and \( (-\sqrt{5}, 6+2 \sqrt{5}) \) Answer saved

          Find the intersection point(s) of the graphs of \( y=\frac{1}{2}(x-2)^{2}+\frac{3}{2} \) and \( y=2(x-2)(x+1) \).
1) \( (2 \pm \sqrt{2}, 1 \pm 6 \sqrt{2}) \)
(2) \( \left(\frac{1}{15}, \frac{4}{9}\right) \)
3 There are no intersection points.
\( 4(\sqrt{5}, 6-2 \sqrt{5}) \) and \( (-\sqrt{5}, 6+2 \sqrt{5}) \)
Answer saved

Find the intersection point(s) of the graphs of y=(1)/(2)(x-2)^2+(3)/(2) and y=2(x-2)(x+1).
1) (2 ±√(2), 1 ± 6 √(2))
(2) ((1)/(15), (4)/(9))
3 There are no intersection points.
4(√(5), 6-2 √(5)) and (-√(5), 6+2 √(5))
Answer saved

Added by Kimberly M.

Calculus: Early Transcendentals

William Briggs, Lyle Cochran, Bernard… 3rd Edition

Chapter 1

Instant Answer

Solved by Expert Linda Hand

Step 1

This means we solve the equation \(\frac{1}{2}(x-2)^{2}+\frac{3}{2} = 2(x-2)(x+1)\). Show more…

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Find the intersection point(s) of the graphs of \( y=\frac{1}{2}(x-2)^{2}+\frac{3}{2} \) and \( y=2(x-2)(x+1) \). 1) \( (2 \pm \sqrt{2}, 1 \pm 6 \sqrt{2}) \) (2) \( \left(\frac{1}{15}, \frac{4}{9}\right) \) 3 There are no intersection points. \( 4(\sqrt{5}, 6-2 \sqrt{5}) \) and \( (-\sqrt{5}, 6+2 \sqrt{5}) \) Answer saved