Find the intervals of increase and decrease and any local extrema of f(x)=3x^4 -4x^3-12x^2 +6
Added by Regina R.
Step 1
To find the intervals of increase and decrease, we first need to compute the first derivative \( f'(x) \). \[ f'(x) = \frac{d}{dx}(3x^4) - \frac{d}{dx}(4x^3) - \frac{d}{dx}(12x^2) + \frac{d}{dx}(6) \] \[ f'(x) = 12x^3 - 12x^2 - 24x \] Show more…
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