00:01
All right, to find out where a function is increasing and decreasing, we need to find the derivative so that we can find the critical values.
00:10
And then once we find the critical values, we'll test to see whether the derivative is positive or negative.
00:17
All right.
00:17
So this are products.
00:18
We're going to use the product rule.
00:20
It's the first times the derivative of the second, two -thirds x minus one to the minus one third, times the derivative of x minus one, which is one.
00:32
First derivative the second plus the second times the derivative of the first.
00:39
Okay, so that is 2x over 3 times x minus 1 to the 1 3 plus x minus 1 to the 2 thirds over 1.
00:52
So i'm going to multiply by 3x minus 1 to the 1 3 3 to the 1 3rd here to get a common denominator.
01:03
So now i have 2x plus.
01:06
Well, when i multiply x minus 1 to the 2 thirds times x.
01:10
Minus 1 to the 1 third, i get x minus 1.
01:13
So i get 3 x minus 1 there over 3x minus 1 to the 1 3.
01:22
So 2x plus 3x minus 3 over 3x minus 1 to the 1 3.
01:34
So 5x minus 3 over 3 times x minus 1 to the 1 3 is the derivative.
01:44
Okay, f prime of x equals 0.
01:48
When 5x minus 3 over 3x minus 1 to the 1 3 3 3 .3 equals 0 over 1.
02:00
Cross multiply, 5x minus 3 equals 0 or x is 3 5ths.
02:08
But there's also another critical point.
02:10
F prime of x is undefined or does not exist when 3x minus 1 to the 1 3 .3.
02:23
So if the denominator is zero, you also get a critical value.
02:30
Divide by three, cube both sides, x equals one.
02:34
So we have critical values at three -fifths and one.
02:40
So now draw a number line.
02:43
And now we're gonna check the derivative, 5x minus three over three x minus one to the one third.
02:51
Pick a number bigger than one, any number that you like, 100, a million, 1 .5.
02:58
Let's just try to 5 times 2 minus 3.
03:03
That is positive over 3 times 5 minus 1 to the 1 3rd.
03:09
That is positive.
03:10
Positive divide by positive is positive.
03:13
So that's increasing.
03:18
All right...