00:02
In this question, fs equals to 3s square minus 3s plus 6 upon s raise to the power 4 plus 5s square plus 4 is given.
00:15
Now this can be written as as plus b upon s square plus 1 and plus cs plus d upon s square plus 2, s square plus 4.
00:30
Now after simplifying in lhs it will be s square minus 3s plus 6 upon s raise to the power 4 plus 5s square plus 4 and here it will be in denominator it will be s square plus 1 and here it will be s square plus 4.
00:53
So this will be as plus b will be multiplied with s square plus 4 and plus cs plus d and this will be multiplied with s square plus 1.
01:06
So here it will be as cube plus as 4 plus bs square plus 4b and plus cs cube plus c plus ds square plus d.
01:25
Then upon s square upon s square plus 1 and here it is s square plus 4 and in lhs it will be same 3s square minus 3s plus 6 upon s raise to the power 4 plus 5s square plus 4.
01:46
Now on comparing both side, on comparing, on comparing both side, so this is equals to this by partial friction method.
02:00
So on comparing both side a plus c equals to 0 because there is no s cube in lhs.
02:08
So this implies a equals to minus c.
02:13
Then next one b s square, so coefficient of s square is b plus d.
02:22
So coefficient of s square here is 3 and coefficient of s, so here coefficient of s is 4a and plus here coefficient of c, so here it is c and coefficient of s here is minus 3 and next the constant term 4b plus d.
02:45
So here the constant term is 6.
02:47
So 4b plus d is 6 and here b plus d.
02:51
Then b plus d equals to 3.
02:53
So on subtracting this d and a will be cancelled out.
02:58
So 3b equals to 3.
03:01
This implies b equals to 1...
