Find the Laplace transform of the function y(t) if y(t) satisfies the differential equation d^2y/dt^2 - 4dy/dt + 3y = 9e^-4t, y(0) = 0, y'(0) = 3 Your answer should be expressed as a function of s using the correct syntax. Laplace transform is Y(s) =
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The Laplace transform of the second derivative is given by: $$\mathcal{L}\{y''(t)\} = s^2Y(s) - sy(0) - y'(0)$$ Since $y(0) = 0$ and $y'(0) = 3$, we have: $$\mathcal{L}\{y''(t)\} = s^2Y(s) - 3$$ The Laplace transform of the first derivative is given Show more…
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