Question

Find the length of the arc of the circular helix with vector equation r(t) = <cos2t, sin2t, 4t> from the point (1,0,0) to the point (1,0,4?)

Name: Find the length of the arc of the circular helix with vector equation r(t) = <cos2t, sin2t, 4t> from the point (1,0,0) to the point (1,0,4?)
Uploaded: 2023-12-08T08:22:34-08:00
Duration: 2 min 28 s
Channel: Adi S
Description: Find the length of the arc of the circular helix with vector equation r(t) = <cos2t, sin2t, 4t> from the point (1,0,0) to the point (1,0,4?)

          Find the length of the arc of the circular helix with vector equation r(t) = <cos2t, sin2t, 4t> from the point (1,0,0) to the point (1,0,4?)

Added by Jose Luis E.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

12/08/2023

Step 1

Step 1: The length of the arc of a curve given by the vector equation r(t) = <x(t), y(t), z(t)> from t=a to t=b is given by the formula: \[ \int_{a}^{b} \sqrt{(x'(t))^2 + (y'(t))^2 + (z'(t))^2} dt \] Show more…

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Find the length of the arc of the circular helix with vector equation r(t)=(t>) from the point (1,0,0) to the point (1,0,4pi ) Find the length of the arc of the circular helix with vector equation r(t)= < cos2t , sin2t,4t> from the point (1,0,0) to the point (1,0,4Tt