Question

Find the length of the curve $x = \int_0^y \sqrt{10 \sec^4 t - 1} dt$, on $-\frac{\pi}{4} \le y \le \frac{\pi}{4}$

Name: Find the length of the curve x = ∫0^y √(10 sec^4 t - 1) dt, on -(π)/(4)≤ y ≤(π)/(4)
Uploaded: 2022-01-25T12:06:23-08:00
Duration: 1 min 44 s
Channel: Bhushan Kumar
Description: Find the length of the curve x = ∫0^y √(10 sec^4 t - 1) dt, on -(π)/(4)≤ y ≤(π)/(4)

          Find the length of the curve $x = \int_0^y \sqrt{10 \sec^4 t - 1} dt$, on $-\frac{\pi}{4} \le y \le \frac{\pi}{4}$

Added by Andrew H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Bhushan Kumar

01/25/2022

Step 1

Given x = ∫₀ʸ √(10sec⁴t - 1) dt, we need to find dx/dy. Using the Fundamental Theorem of Calculus, we have dx/dy = √(10sec⁴y - 1). Show more…

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Find the length of the curve x=int_0^y sqrt(10sec^(4)t-1)dt, on -(pi )/(4)<=y<=(pi )/(4). T Find the length of the curve x = 10 sec41dt on TT 4

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Find the length of the curve $x = \int_0^y \sqrt{10 \sec^4 t - 1} dt$, on $-\frac{\pi}{4} \le y \le \frac{\pi}{4}$

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