Find the limit. (If the limit is infinite, enter '?' or '-?', as appropriate. If the limit does

Name: Find the limit. (If the limit is infinite, enter '?' or '-?', as appropriate. If the limit does not otherwise exist, enter DNE.) limx →? ( (sin^2(x))/(x^2 + 4) )
Uploaded: 2022-09-19T09:48:15-08:00
Duration: 2 min 13 s
Channel: Adi S
Description: Find the limit. (If the limit is infinite, enter '?' or '-?', as appropriate. If the limit does not otherwise exist, enter DNE.) limx →? ( (sin^2(x))/(x^2 + 4) )

Step 1: Recall that as x approaches infinity, sin(x) oscillates between -1 and 1, but never exce

Question

Find the limit. (If the limit is infinite, enter '?' or '-?', as appropriate. If the limit does not otherwise exist, enter DNE.) \lim_{x \to ?} \left( \frac{\sin^2(x)}{x^2 + 4} \right)

          Find the limit. (If the limit is infinite, enter '?' or '-?', as appropriate. If the limit does not otherwise exist, enter DNE.) \lim_{x \to ?} \left( \frac{\sin^2(x)}{x^2 + 4} \right)

Find the limit. (If the limit is infinite, enter '?' or '-?', as appropriate. If the limit does not otherwise exist, enter DNE.) limx →? ( (sin^2(x))/(x^2 + 4) )

Added by Guillermo L.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

09/19/2022

Step 1

Therefore, sin^2(x) will always be between 0 and 1. Show more…

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Find the limit. (If the limit is infinite, enter 'infty' or '-infty', as appropriate. If the limit does not otherwise exist, enter DNE.) lim_{x oinfty}left(frac{sin^2(x)}{x^2+4} ight) Find the limit. If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.