00:01
In this problem we are provided with the sequence whose nth term is negative sign of n divided by 6 times n.
00:12
We are asked to check whether the given sequence converges or diverges.
00:21
And if the sequence converges, then we need to find out the value of the limit to which it converges.
00:29
So here it means that we need to check if limit n tends to infinity negative sign of n over 6 times n exists or not.
00:44
So if it exists, we say that the sequence converges and if it does not exist, then we say that the sequence diverges.
00:53
So here, let us closely look at the given function.
00:58
So here we know that the value of sine n must always lie between negative 1 and positive 1.
01:07
So next, since we have negative sign of n, we multiply throughout with negative 1.
01:13
So this changes the inequality.
01:16
We have 1 greater than or equal to negative sign of n is greater than or equal to negative 1.
01:23
Next, we divide this by 6 times n...