Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. $$ \lim_{x \to 0} \sin(9x) \csc(7x) $$
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First, let's rewrite the expression using the definition of cosecant: $\csc(\theta) = \frac{1}{\sin(\theta)}$. So, the expression becomes: $$ \lim_{x \to 0} \sin(9x) \frac{1}{\sin(7x)} = \lim_{x \to 0} \frac{\sin(9x)}{\sin(7x)} $$ Show more…
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