00:01
To evaluate this limit, the first thing we have to do is to directly plug in the value of x, which is 2, to the function x minus 2 raised to the qubit of x minus 2.
00:12
So then we will get 2 minus 2 raise to the qubit of 2 minus 2, which is equal to 0, race to 0 on indeterminate form.
00:23
And because it's indeterminate, we need to rewrite our function.
00:27
Now for this, we will apply logarithmic properties.
00:32
Now let's say y is equal to x minus 2 raise to the quibrate of x minus 2.
00:39
Then applying natural log to both sides, ln of y equals the natural log of x minus 2 raise to the quibrate of x minus 2, which is the same as l and y equal to the qubit of x minus 2 times the n.
00:57
Natural log of x minus 2.
01:00
And then we can rewrite this even further because the cubrit of x minus 2 is the same as x minus 2 race to 1 3rd...