Find the linearization of f(x)= tan x at x = π / 4. Use the linearization to approximate f (0.75).
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Given \(f(x) = \tan x\), the linearization at \(x = a\) is given by: \[L(x) = f(a) + f'(a)(x - a)\] Plugging in \(a = \frac{\pi}{4}\) and \(f(x) = \tan x\), we have: \[L(x) = \tan\left(\frac{\pi}{4}\right) + \sec^2\left(\frac{\pi}{4}\right)(x - Show more…
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